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Machine Learning Engineer Nanodegree

Unsupervised Learning

Project: Creating Customer Segments

Welcome to the third project of the Machine Learning Engineer Nanodegree! In this notebook, some template code has already been provided for you, and it will be your job to implement the additional functionality necessary to successfully complete this project. Sections that begin with 'Implementation' in the header indicate that the following block of code will require additional functionality which you must provide. Instructions will be provided for each section and the specifics of the implementation are marked in the code block with a 'TODO' statement. Please be sure to read the instructions carefully!

In addition to implementing code, there will be questions that you must answer which relate to the project and your implementation. Each section where you will answer a question is preceded by a 'Question X' header. Carefully read each question and provide thorough answers in the following text boxes that begin with 'Answer:'. Your project submission will be evaluated based on your answers to each of the questions and the implementation you provide.

Note: Code and Markdown cells can be executed using the Shift + Enter keyboard shortcut. In addition, Markdown cells can be edited by typically double-clicking the cell to enter edit mode.

Getting Started

In this project, you will analyze a dataset containing data on various customers' annual spending amounts (reported in monetary units) of diverse product categories for internal structure. One goal of this project is to best describe the variation in the different types of customers that a wholesale distributor interacts with. Doing so would equip the distributor with insight into how to best structure their delivery service to meet the needs of each customer.

The dataset for this project can be found on the UCI Machine Learning Repository. For the purposes of this project, the features 'Channel' and 'Region' will be excluded in the analysis — with focus instead on the six product categories recorded for customers.

Run the code block below to load the wholesale customers dataset, along with a few of the necessary Python libraries required for this project. You will know the dataset loaded successfully if the size of the dataset is reported.

In [267]:
# Import libraries necessary for this project
import numpy as np
import pandas as pd
from IPython.display import display # Allows the use of display() for DataFrames

# Import supplementary visualizations code visuals.py
import visuals as vs

# Pretty display for notebooks
%matplotlib inline

# Load the wholesale customers dataset
try:
    data = pd.read_csv("customers.csv")
    data.drop(['Region', 'Channel'], axis = 1, inplace = True)
    print "Wholesale customers dataset has {} samples with {} features each.".format(*data.shape)
except:
    print "Dataset could not be loaded. Is the dataset missing?"
Wholesale customers dataset has 440 samples with 6 features each.

Data Exploration

In this section, you will begin exploring the data through visualizations and code to understand how each feature is related to the others. You will observe a statistical description of the dataset, consider the relevance of each feature, and select a few sample data points from the dataset which you will track through the course of this project.

Run the code block below to observe a statistical description of the dataset. Note that the dataset is composed of six important product categories: 'Fresh', 'Milk', 'Grocery', 'Frozen', 'Detergents_Paper', and 'Delicatessen'. Consider what each category represents in terms of products you could purchase.

In [268]:
# Display a description of the dataset
display(data.describe())
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
count 440.000000 440.000000 440.000000 440.000000 440.000000 440.000000
mean 12000.297727 5796.265909 7951.277273 3071.931818 2881.493182 1524.870455
std 12647.328865 7380.377175 9503.162829 4854.673333 4767.854448 2820.105937
min 3.000000 55.000000 3.000000 25.000000 3.000000 3.000000
25% 3127.750000 1533.000000 2153.000000 742.250000 256.750000 408.250000
50% 8504.000000 3627.000000 4755.500000 1526.000000 816.500000 965.500000
75% 16933.750000 7190.250000 10655.750000 3554.250000 3922.000000 1820.250000
max 112151.000000 73498.000000 92780.000000 60869.000000 40827.000000 47943.000000

Implementation: Selecting Samples

To get a better understanding of the customers and how their data will transform through the analysis, it would be best to select a few sample data points and explore them in more detail. In the code block below, add three indices of your choice to the indices list which will represent the customers to track. It is suggested to try different sets of samples until you obtain customers that vary significantly from one another.

In [269]:
# TODO: Select three indices of your choice you wish to sample from the dataset
indices = [95, 176, 200]

# Create a DataFrame of the chosen samples
samples = pd.DataFrame(data.loc[indices], columns = data.keys()).reset_index(drop = True)
print "Chosen samples of wholesale customers dataset:"
display(samples)
Chosen samples of wholesale customers dataset:
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
0 3 2920 6252 440 223 709
1 45640 6958 6536 7368 1532 230
2 3067 13240 23127 3941 9959 731

Question 1

Consider the total purchase cost of each product category and the statistical description of the dataset above for your sample customers.
What kind of establishment (customer) could each of the three samples you've chosen represent?
Hint: Examples of establishments include places like markets, cafes, and retailers, among many others. Avoid using names for establishments, such as saying "McDonalds" when describing a sample customer as a restaurant.

Answer:

  1. I think the first customer is likely to be a small corner shop, given that they order very little fresh ingredients (3 vs a mean of 12000.3) while they do order a proportionately higher amount of Milk (2920 vs a mean of 5796.27) and Grocery type foods (6252 vs a mean of 7951.28) than other types of goods. Corner shops typically have a small frozen section (440 vs a mean of 3071.93) and household items area (223 vs a mean of 2881.49), but can sometimes have a large delicatessen area (709 vs a mean of 1524.87) depending on the demographic makeup of the area the shop is in. Looking at the heatmap of normalized expenditures below, this sample purchases much less goods overall than other customers, but seems to purchase proportionately more Milk, Grocery, and Delicatessen goods than other types of goods.

  2. The second customer is more likely to be a big market-like shop, with a huge fresh produce section (likely organic produce given the cost, with an expenditure of 45640 compared to a mean of 12000.3) and smaller and equal areas for milk (6958 vs a mean of 5796.27), normal groceries (6536 vs a mean of 7951.28), and frozen foods (7368 vs a mean of 3071.93). I would assume a place like this would also have a bigger delicatessen area, though it appears not to be the case (230 vs a mean of 1524.87). Looking at the heatmap of normalized expenditures below, this sample purchases significantly more fresh produce than other customers and substantially more frozen goods than other customers, but is closer to the mean for both Milk and Grocery products, and has below average consumption of Detergents_Paper and Delicatessen products.

  3. The final customer strikes me as a typical supermarket with a modest fresh produce area (3067 vs a mean of 12000.3), but a shop where you're more likely to go for typical grocery items like bread, cereals, tins of food, etc. (23127 vs a mean of 7951.28). These kind of stores typically have a substantial dairy selection (13240 vs a mean of 5796.27) and frozen area (3941 vs a mean of 3071.93), and also have aisles dedicated solely to household items like detergent and paper towels (9959 vs a mean of 2881.49). You're less likely to find a delicatessen area in a store like this (731 vs a mean of 1524.87), though there would appear to be a small part of the store that caters to customers interested in those types of goods. Looking at the heatmap of normalized expenditures below, this sample purchases significantly more Milk, Grocery, and Delicatessen_Paper products, slightly more frozen goods and slightly less delicatessen products, and a below average amount of fresh produce than other customers.
In [270]:
import seaborn as sns

sns.heatmap((samples-data.mean())/data.std(ddof=0), annot=True, cbar=False, square=True)
Out[270]:
<matplotlib.axes._subplots.AxesSubplot at 0x10fb86cd0>

Implementation: Feature Relevance

One interesting thought to consider is if one (or more) of the six product categories is actually relevant for understanding customer purchasing. That is to say, is it possible to determine whether customers purchasing some amount of one category of products will necessarily purchase some proportional amount of another category of products? We can make this determination quite easily by training a supervised regression learner on a subset of the data with one feature removed, and then score how well that model can predict the removed feature.

In the code block below, you will need to implement the following:

  • Assign new_data a copy of the data by removing a feature of your choice using the DataFrame.drop function.
  • Use sklearn.cross_validation.train_test_split to split the dataset into training and testing sets.
    • Use the removed feature as your target label. Set a test_size of 0.25 and set a random_state.
  • Import a decision tree regressor, set a random_state, and fit the learner to the training data.
  • Report the prediction score of the testing set using the regressor's score function.
In [271]:
print new_data
     Fresh   Milk  Frozen  Detergents_Paper  Delicatessen
0    12669   9656     214              2674          1338
1     7057   9810    1762              3293          1776
2     6353   8808    2405              3516          7844
3    13265   1196    6404               507          1788
4    22615   5410    3915              1777          5185
5     9413   8259     666              1795          1451
6    12126   3199     480              3140           545
7     7579   4956    1669              3321          2566
8     5963   3648     425              1716           750
9     6006  11093    1159              7425          2098
10    3366   5403    4400              5977          1744
11   13146   1124    1420               549           497
12   31714  12319     287              3881          2931
13   21217   6208    3095              6707           602
14   24653   9465     294              5058          2168
15   10253   1114     397               964           412
16    1020   8816     134              4508          1080
17    5876   6157     839               370          4478
18   18601   6327    2205              2767          3181
19    7780   2495     669              2518           501
20   17546   4519    1066              2259          2124
21    5567    871    3383               375           569
22   31276   1917    9408              2381          4334
23   26373  36423    5154              4337         16523
24   22647   9776    2915              4482          5778
25   16165   4230     201              4003            57
26    9898    961    3151               242           833
27   14276    803     485               100           518
28    4113  20484    1158              8604          5206
29   43088   2100    1200              1107           823
..     ...    ...     ...               ...           ...
410   6633   2096    1389              1860          1892
411   2126   3289    1535               235          4365
412     97   3605      98              2970            62
413   4983   4859   17866               912          2435
414   5969   1990    5679              1135           290
415   7842   6046    1691              3540          1874
416   4389  10940     848              6728           993
417   5065   5499     364              3485          1063
418    660   8494     133              6740           776
419   8861   3783     633              1580          1521
420   4456   5266      25              6818          1393
421  17063   4847    1031              3415          1784
422  26400   1377     830               948          1218
423  17565   3686    1059              1803           668
424  16980   2884     874              3213           249
425  11243   2408   15348               108          1886
426  13134   9347    3141              5079          1894
427  31012  16687   15082               439          1163
428   3047   5970    2198               850           317
429   8607   1750      47                84          2501
430   3097   4230     575               241          2080
431   8533   5506   13486              1377          1498
432  21117   1162     269              1328           395
433   1982   3218    1541               356          1449
434  16731   3922     688              2371           838
435  29703  12051   13135               182          2204
436  39228   1431    4510                93          2346
437  14531  15488     437             14841          1867
438  10290   1981    1038               168          2125
439   2787   1698      65               477            52

[440 rows x 5 columns]
In [272]:
from sklearn.model_selection import train_test_split
from sklearn.tree import DecisionTreeRegressor

# TODO: Make a copy of the DataFrame, using the 'drop' function to drop the given feature
new_data = data.copy()
new_data.drop(['Grocery'], axis=1, inplace = True)

# TODO: Split the data into training and testing sets using the given feature as the target
X_train, X_test, y_train, y_test = train_test_split(new_data, data['Grocery'], test_size = 0.25, random_state = 1)

# TODO: Create a decision tree regressor and fit it to the training set
regressor = DecisionTreeRegressor(random_state = 1)
regressor.fit(X_train, y_train)

# TODO: Report the score of the prediction using the testing set
score = regressor.score(X_test, y_test)
print score
0.795768311576

Question 2

Which feature did you attempt to predict? What was the reported prediction score? Is this feature necessary for identifying customers' spending habits?
Hint: The coefficient of determination, R^2, is scored between 0 and 1, with 1 being a perfect fit. A negative R^2 implies the model fails to fit the data.

Answer:

I attempted to predict the 'Grocery' feature. The reported prediction score was 0.7958, which means that the model was able to predict its value reasonably well and could mean that it's not a necessary feature for identifying customers' spending habits. Other features could be used to predict customers' purchasing behaviour of groceries with a reasonable degree of accuracy.

In [273]:
from sklearn.cross_validation import train_test_split
from sklearn.tree import DecisionTreeRegressor

def calculate_r_2_for_feature(data,feature):
    new_data = data.drop(feature, axis=1)

    X_train, X_test,y_train, y_test = train_test_split(new_data,data[feature],test_size=0.25)

    regressor = DecisionTreeRegressor()
    regressor.fit(X_train,y_train)

    score = regressor.score(X_test,y_test)
    return score

def r_2_mean(data,feature,runs=200):
    return np.array([calculate_r_2_for_feature(data,feature) 
                     for _ in range(200) ]).mean().round(4)

print "{0:17} {1}".format("Fresh: ", r_2_mean(data,'Fresh'))
print "{0:17} {1}".format("Milk: ", r_2_mean(data,'Milk'))
print "{0:17} {1}".format("Grocery: ", r_2_mean(data,'Grocery'))
print "{0:17} {1}".format("Frozen: ", r_2_mean(data,'Frozen'))
print "{0:17} {1}".format("Detergents_Paper: ", r_2_mean(data,'Detergents_Paper'))
print "{0:17} {1}".format("Delicatessen: ", r_2_mean(data,'Delicatessen'))
Fresh:            -0.7802
Milk:             0.1073
Grocery:          0.6782
Frozen:           -1.2441
Detergents_Paper:  0.685
Delicatessen:     -3.1109

Visualize Feature Distributions

To get a better understanding of the dataset, we can construct a scatter matrix of each of the six product features present in the data. If you found that the feature you attempted to predict above is relevant for identifying a specific customer, then the scatter matrix below may not show any correlation between that feature and the others. Conversely, if you believe that feature is not relevant for identifying a specific customer, the scatter matrix might show a correlation between that feature and another feature in the data. Run the code block below to produce a scatter matrix.

In [274]:
# Produce a scatter matrix for each pair of features in the data
pd.scatter_matrix(data, alpha = 0.3, figsize = (14,8), diagonal = 'kde');
In [275]:
corr = data.corr()
mask = np.zeros_like(corr)
mask[np.triu_indices_from(mask, 1)] = True
with sns.axes_style("white"):
    ax = sns.heatmap(corr, mask=mask, square=True, annot=True,
                     cmap='RdBu', fmt='+.3f')

Question 3

Are there any pairs of features which exhibit some degree of correlation? Does this confirm or deny your suspicions about the relevance of the feature you attempted to predict? How is the data for those features distributed?
Hint: Is the data normally distributed? Where do most of the data points lie?

Answer:

It appears that Grocery and Detergents_Paper have the strongest correlation of the pairs. It also looks like there is some correlation between Detergents_Paper and Milk, and Grocery and Milk. This confirms my suspicion above that Grocery was correlated with some other features that would allow for its value to be predicted with some degree of accuracy. All of the distributions appear to be skewed to the right, with more points hovering closer to the origin and some larger points extending it to the right. The shape of the distributions of Detergents_Paper, Grocery, and Milk are all quite similar.

Data Preprocessing

In this section, you will preprocess the data to create a better representation of customers by performing a scaling on the data and detecting (and optionally removing) outliers. Preprocessing data is often times a critical step in assuring that results you obtain from your analysis are significant and meaningful.

Implementation: Feature Scaling

If data is not normally distributed, especially if the mean and median vary significantly (indicating a large skew), it is most often appropriate to apply a non-linear scaling — particularly for financial data. One way to achieve this scaling is by using a Box-Cox test, which calculates the best power transformation of the data that reduces skewness. A simpler approach which can work in most cases would be applying the natural logarithm.

In the code block below, you will need to implement the following:

  • Assign a copy of the data to log_data after applying logarithmic scaling. Use the np.log function for this.
  • Assign a copy of the sample data to log_samples after applying logarithmic scaling. Again, use np.log.
In [276]:
# TODO: Scale the data using the natural logarithm
log_data = np.log(data.copy())

# TODO: Scale the sample data using the natural logarithm
log_samples = np.log(samples)

# Produce a scatter matrix for each pair of newly-transformed features
pd.scatter_matrix(log_data, alpha = 0.3, figsize = (14,8), diagonal = 'kde');

Observation

After applying a natural logarithm scaling to the data, the distribution of each feature should appear much more normal. For any pairs of features you may have identified earlier as being correlated, observe here whether that correlation is still present (and whether it is now stronger or weaker than before).

Run the code below to see how the sample data has changed after having the natural logarithm applied to it.

In [277]:
# Display the log-transformed sample data
display(log_samples)
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
0 1.098612 7.979339 8.740657 6.086775 5.407172 6.563856
1 10.728540 8.847647 8.785081 8.904902 7.334329 5.438079
2 8.028455 9.490998 10.048756 8.279190 9.206232 6.594413

Implementation: Outlier Detection

Detecting outliers in the data is extremely important in the data preprocessing step of any analysis. The presence of outliers can often skew results which take into consideration these data points. There are many "rules of thumb" for what constitutes an outlier in a dataset. Here, we will use Tukey's Method for identfying outliers: An outlier step is calculated as 1.5 times the interquartile range (IQR). A data point with a feature that is beyond an outlier step outside of the IQR for that feature is considered abnormal.

In the code block below, you will need to implement the following:

  • Assign the value of the 25th percentile for the given feature to Q1. Use np.percentile for this.
  • Assign the value of the 75th percentile for the given feature to Q3. Again, use np.percentile.
  • Assign the calculation of an outlier step for the given feature to step.
  • Optionally remove data points from the dataset by adding indices to the outliers list.

NOTE: If you choose to remove any outliers, ensure that the sample data does not contain any of these points!
Once you have performed this implementation, the dataset will be stored in the variable good_data.

In [278]:
from collections import Counter

# For each feature find the data points with extreme high or low values
for feature in log_data.keys():
    
    # TODO: Calculate Q1 (25th percentile of the data) for the given feature
    Q1 = np.percentile(log_data[feature], 25)
    
    # TODO: Calculate Q3 (75th percentile of the data) for the given feature
    Q3 = np.percentile(log_data[feature], 75)
    
    # TODO: Use the interquartile range to calculate an outlier step (1.5 times the interquartile range)
    step = (Q3 - Q1) * 1.5
    
    # Display the outliers
    print "Data points considered outliers for the feature '{}':".format(feature)
    display(log_data[~((log_data[feature] >= Q1 - step) & (log_data[feature] <= Q3 + step))])
    
# OPTIONAL: Select the indices for data points you wish to remove
outliers  = []

# Remove the outliers, if any were specified
good_data = log_data.drop(log_data.index[outliers]).reset_index(drop = True)
Data points considered outliers for the feature 'Fresh':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
65 4.442651 9.950323 10.732651 3.583519 10.095388 7.260523
66 2.197225 7.335634 8.911530 5.164786 8.151333 3.295837
81 5.389072 9.163249 9.575192 5.645447 8.964184 5.049856
95 1.098612 7.979339 8.740657 6.086775 5.407172 6.563856
96 3.135494 7.869402 9.001839 4.976734 8.262043 5.379897
128 4.941642 9.087834 8.248791 4.955827 6.967909 1.098612
171 5.298317 10.160530 9.894245 6.478510 9.079434 8.740337
193 5.192957 8.156223 9.917982 6.865891 8.633731 6.501290
218 2.890372 8.923191 9.629380 7.158514 8.475746 8.759669
304 5.081404 8.917311 10.117510 6.424869 9.374413 7.787382
305 5.493061 9.468001 9.088399 6.683361 8.271037 5.351858
338 1.098612 5.808142 8.856661 9.655090 2.708050 6.309918
353 4.762174 8.742574 9.961898 5.429346 9.069007 7.013016
355 5.247024 6.588926 7.606885 5.501258 5.214936 4.844187
357 3.610918 7.150701 10.011086 4.919981 8.816853 4.700480
412 4.574711 8.190077 9.425452 4.584967 7.996317 4.127134
Data points considered outliers for the feature 'Milk':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
86 10.039983 11.205013 10.377047 6.894670 9.906981 6.805723
98 6.220590 4.718499 6.656727 6.796824 4.025352 4.882802
154 6.432940 4.007333 4.919981 4.317488 1.945910 2.079442
356 10.029503 4.897840 5.384495 8.057377 2.197225 6.306275
Data points considered outliers for the feature 'Grocery':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
75 9.923192 7.036148 1.098612 8.390949 1.098612 6.882437
154 6.432940 4.007333 4.919981 4.317488 1.945910 2.079442
Data points considered outliers for the feature 'Frozen':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
38 8.431853 9.663261 9.723703 3.496508 8.847360 6.070738
57 8.597297 9.203618 9.257892 3.637586 8.932213 7.156177
65 4.442651 9.950323 10.732651 3.583519 10.095388 7.260523
145 10.000569 9.034080 10.457143 3.737670 9.440738 8.396155
175 7.759187 8.967632 9.382106 3.951244 8.341887 7.436617
264 6.978214 9.177714 9.645041 4.110874 8.696176 7.142827
325 10.395650 9.728181 9.519735 11.016479 7.148346 8.632128
420 8.402007 8.569026 9.490015 3.218876 8.827321 7.239215
429 9.060331 7.467371 8.183118 3.850148 4.430817 7.824446
439 7.932721 7.437206 7.828038 4.174387 6.167516 3.951244
Data points considered outliers for the feature 'Detergents_Paper':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
75 9.923192 7.036148 1.098612 8.390949 1.098612 6.882437
161 9.428190 6.291569 5.645447 6.995766 1.098612 7.711101
Data points considered outliers for the feature 'Delicatessen':
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
66 2.197225 7.335634 8.911530 5.164786 8.151333 3.295837
109 7.248504 9.724899 10.274568 6.511745 6.728629 1.098612
128 4.941642 9.087834 8.248791 4.955827 6.967909 1.098612
137 8.034955 8.997147 9.021840 6.493754 6.580639 3.583519
142 10.519646 8.875147 9.018332 8.004700 2.995732 1.098612
154 6.432940 4.007333 4.919981 4.317488 1.945910 2.079442
183 10.514529 10.690808 9.911952 10.505999 5.476464 10.777768
184 5.789960 6.822197 8.457443 4.304065 5.811141 2.397895
187 7.798933 8.987447 9.192075 8.743372 8.148735 1.098612
203 6.368187 6.529419 7.703459 6.150603 6.860664 2.890372
233 6.871091 8.513988 8.106515 6.842683 6.013715 1.945910
285 10.602965 6.461468 8.188689 6.948897 6.077642 2.890372
289 10.663966 5.655992 6.154858 7.235619 3.465736 3.091042
343 7.431892 8.848509 10.177932 7.283448 9.646593 3.610918

Question 4

Are there any data points considered outliers for more than one feature based on the definition above? Should these data points be removed from the dataset? If any data points were added to the outliers list to be removed, explain why.

Answer:

75 is considered an outlier for both the Grocery and Detergents_Paper features; 154 is considered an outlier for all of Milk, Grocery, and Delicatessen features; 65 is in Fresh and Frozen; 66 is in Delicatessen and Fresh; 128 is in Delicatessen and Fresh. I think these data points should be removed from the dataset because they were outliers for more than one feature, and therefore may reduce the predictive capability of our model if it is trained on these noisy datapoints. Interestingly, one of the datapoints I selected for the sample, 95, turned out to be an outlier due to the amount of Fresh produce the customer purchased.

Feature Transformation

In this section you will use principal component analysis (PCA) to draw conclusions about the underlying structure of the wholesale customer data. Since using PCA on a dataset calculates the dimensions which best maximize variance, we will find which compound combinations of features best describe customers.

Implementation: PCA

Now that the data has been scaled to a more normal distribution and has had any necessary outliers removed, we can now apply PCA to the good_data to discover which dimensions about the data best maximize the variance of features involved. In addition to finding these dimensions, PCA will also report the explained variance ratio of each dimension — how much variance within the data is explained by that dimension alone. Note that a component (dimension) from PCA can be considered a new "feature" of the space, however it is a composition of the original features present in the data.

In the code block below, you will need to implement the following:

  • Import sklearn.decomposition.PCA and assign the results of fitting PCA in six dimensions with good_data to pca.
  • Apply a PCA transformation of log_samples using pca.transform, and assign the results to pca_samples.
In [279]:
from sklearn.decomposition import PCA
# TODO: Apply PCA by fitting the good data with the same number of dimensions as features
pca = PCA(n_components=6)
pca.fit(good_data)

# TODO: Transform log_samples using the PCA fit above
pca_samples = pca.transform(log_samples)

# Generate PCA results plot
pca_results = vs.pca_results(good_data, pca)

Question 5

How much variance in the data is explained in total by the first and second principal component? What about the first four principal components? Using the visualization provided above, discuss what the first four dimensions best represent in terms of customer spending.
Hint: A positive increase in a specific dimension corresponds with an increase of the positive-weighted features and a decrease of the negative-weighted features. The rate of increase or decrease is based on the indivdual feature weights.

Answer:

The first and second principal components explain .719 of the variance of the data, while the first four principal components explain .9314 of the variance of the data.

Dimension 1 primarily paired Detergents_Paper, Milk, and Grocery together; this dimension represents purchases of everyday household goods, likely by retailers.

Dimension 2 primarily paired Fresh, Frozen, and Delicatessen together, though all products are weighted in the same direction; this dimension represents that purchases of fresh produce, frozen goods, and delicatessen products, which could be typical of a restaurant or cafe.

Dimension 3 weakly paired Delicatessen and Frozen together, and strongly negated Fresh; this dimension represents purchases of delicatessen products and frozen goods, which could be typical of US convenience store-like companies (though the companies are based in Portugal).

Dimension 4 negatively paired Frozen against Delicatessen and to a lesser extent Fresh, and positively paired Detergents_Paper; this dimension could represent purchases by a gas station shop.

Observation

Run the code below to see how the log-transformed sample data has changed after having a PCA transformation applied to it in six dimensions. Observe the numerical value for the first four dimensions of the sample points. Consider if this is consistent with your initial interpretation of the sample points.

In [280]:
# Display sample log-data after having a PCA transformation applied
display(pd.DataFrame(np.round(pca_samples, 4), columns = pca_results.index.values))
Dimension 1 Dimension 2 Dimension 3 Dimension 4 Dimension 5 Dimension 6
0 -0.5721 5.9329 5.0156 0.4633 0.8491 -0.3529
1 -0.0451 -1.6903 -1.7866 1.6343 0.5154 0.1672
2 -3.0182 -0.3952 0.1711 1.5640 0.1637 -0.0694

Implementation: Dimensionality Reduction

When using principal component analysis, one of the main goals is to reduce the dimensionality of the data — in effect, reducing the complexity of the problem. Dimensionality reduction comes at a cost: Fewer dimensions used implies less of the total variance in the data is being explained. Because of this, the cumulative explained variance ratio is extremely important for knowing how many dimensions are necessary for the problem. Additionally, if a signifiant amount of variance is explained by only two or three dimensions, the reduced data can be visualized afterwards.

In the code block below, you will need to implement the following:

  • Assign the results of fitting PCA in two dimensions with good_data to pca.
  • Apply a PCA transformation of good_data using pca.transform, and assign the results to reduced_data.
  • Apply a PCA transformation of log_samples using pca.transform, and assign the results to pca_samples.
In [281]:
# TODO: Apply PCA by fitting the good data with only two dimensions
pca = PCA(n_components=2)
pca.fit(good_data)

# TODO: Transform the good data using the PCA fit above
reduced_data = pca.transform(good_data)

# TODO: Transform log_samples using the PCA fit above
pca_samples = pca.transform(log_samples)

# Create a DataFrame for the reduced data
reduced_data = pd.DataFrame(reduced_data, columns = ['Dimension 1', 'Dimension 2'])

Observation

Run the code below to see how the log-transformed sample data has changed after having a PCA transformation applied to it using only two dimensions. Observe how the values for the first two dimensions remains unchanged when compared to a PCA transformation in six dimensions.

In [282]:
# Display sample log-data after applying PCA transformation in two dimensions
display(pd.DataFrame(np.round(pca_samples, 4), columns = ['Dimension 1', 'Dimension 2']))
Dimension 1 Dimension 2
0 -0.5721 5.9329
1 -0.0451 -1.6903
2 -3.0182 -0.3952

Visualizing a Biplot

A biplot is a scatterplot where each data point is represented by its scores along the principal components. The axes are the principal components (in this case Dimension 1 and Dimension 2). In addition, the biplot shows the projection of the original features along the components. A biplot can help us interpret the reduced dimensions of the data, and discover relationships between the principal components and original features.

Run the code cell below to produce a biplot of the reduced-dimension data.

In [283]:
# Create a biplot
vs.biplot(good_data, reduced_data, pca)
Out[283]:
<matplotlib.axes._subplots.AxesSubplot at 0x116b78650>

Observation

Once we have the original feature projections (in red), it is easier to interpret the relative position of each data point in the scatterplot. For instance, a point the lower right corner of the figure will likely correspond to a customer that spends a lot on 'Milk', 'Grocery' and 'Detergents_Paper', but not so much on the other product categories.

From the biplot, which of the original features are most strongly correlated with the first component? What about those that are associated with the second component? Do these observations agree with the pca_results plot you obtained earlier?

Clustering

In this section, you will choose to use either a K-Means clustering algorithm or a Gaussian Mixture Model clustering algorithm to identify the various customer segments hidden in the data. You will then recover specific data points from the clusters to understand their significance by transforming them back into their original dimension and scale.

Question 6

What are the advantages to using a K-Means clustering algorithm? What are the advantages to using a Gaussian Mixture Model clustering algorithm? Given your observations about the wholesale customer data so far, which of the two algorithms will you use and why?

Answer:

The major advantages of using a K-Means clustering algorithm are that it scales well to a large number of samples and always converges, however this converegence can sometimes be to a local minima and when this occurs it needs to be re-run. The Gaussian Mixture Model clustering algorithm, specifically Expectation Maximisation, is a more general case of a K-Means clustering algorithm. Its advantages are that it's quick to run, and doesn't require a distribution to be normal for it to work. It does also suffer from the possibility of 'getting stuck' in a local minima, at which point it would need to be re-run, though it never fully converges (though the step changes in the probabilities become small enough that it effectively does converge). Given that we know that the first and second principal components explain 71.9% of the variance, meaning we have a rough idea of how many clusters to expect, I think we should use a K-means clustering algorithm where the number of clusters is 2, though we should be sure to check how it performs for different numbers of clusters.

Implementation: Creating Clusters

Depending on the problem, the number of clusters that you expect to be in the data may already be known. When the number of clusters is not known a priori, there is no guarantee that a given number of clusters best segments the data, since it is unclear what structure exists in the data — if any. However, we can quantify the "goodness" of a clustering by calculating each data point's silhouette coefficient. The silhouette coefficient for a data point measures how similar it is to its assigned cluster from -1 (dissimilar) to 1 (similar). Calculating the mean silhouette coefficient provides for a simple scoring method of a given clustering.

In the code block below, you will need to implement the following:

  • Fit a clustering algorithm to the reduced_data and assign it to clusterer.
  • Predict the cluster for each data point in reduced_data using clusterer.predict and assign them to preds.
  • Find the cluster centers using the algorithm's respective attribute and assign them to centers.
  • Predict the cluster for each sample data point in pca_samples and assign them sample_preds.
  • Import sklearn.metrics.silhouette_score and calculate the silhouette score of reduced_data against preds.
  • Assign the silhouette score to score and print the result.
In [284]:
from sklearn.metrics import silhouette_score
from sklearn.cluster import KMeans

# TODO: Apply your clustering algorithm of choice to the reduced data 
clusterer = KMeans(n_clusters=2, random_state=1)
clusterer.fit(reduced_data)

# TODO: Predict the cluster for each data point
preds = clusterer.predict(reduced_data)

# TODO: Find the cluster centers
centers = clusterer.cluster_centers_

# TODO: Predict the cluster for each transformed sample data point
sample_preds = clusterer.predict(pca_samples)

# TODO: Calculate the mean silhouette coefficient for the number of clusters chosen
score = silhouette_score(reduced_data, preds, random_state=1)
print score
0.419166083203

Question 7

Report the silhouette score for several cluster numbers you tried. Of these, which number of clusters has the best silhouette score?

Answer:

  • Two clusters: 0.4192
  • Three clusters: 0.3943
  • Four clusters: 0.3302
  • Five clusters: 0.3478
  • Six clusters: 0.3602
  • Seven clsuters: 0.3641
  • Eight clusters: 0.3417
  • Nine clusters: 0.3517
  • Ten clusters: 0.3653

Of these, the best silhouette score was computed from two clusters, with a score of 0.4192.

Cluster Visualization

Once you've chosen the optimal number of clusters for your clustering algorithm using the scoring metric above, you can now visualize the results by executing the code block below. Note that, for experimentation purposes, you are welcome to adjust the number of clusters for your clustering algorithm to see various visualizations. The final visualization provided should, however, correspond with the optimal number of clusters.

In [285]:
# Display the results of the clustering from implementation
vs.cluster_results(reduced_data, preds, centers, pca_samples)

Implementation: Data Recovery

Each cluster present in the visualization above has a central point. These centers (or means) are not specifically data points from the data, but rather the averages of all the data points predicted in the respective clusters. For the problem of creating customer segments, a cluster's center point corresponds to the average customer of that segment. Since the data is currently reduced in dimension and scaled by a logarithm, we can recover the representative customer spending from these data points by applying the inverse transformations.

In the code block below, you will need to implement the following:

  • Apply the inverse transform to centers using pca.inverse_transform and assign the new centers to log_centers.
  • Apply the inverse function of np.log to log_centers using np.exp and assign the true centers to true_centers.
In [286]:
# TODO: Inverse transform the centers
log_centers = pca.inverse_transform(centers)

# TODO: Exponentiate the centers
true_centers = np.exp(log_centers)

# Display the true centers
segments = ['Segment {}'.format(i) for i in range(0,len(centers))]
true_centers = pd.DataFrame(np.round(true_centers), columns = data.keys())
true_centers.index = segments
display(true_centers)
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
Segment 0 3570.0 7749.0 12463.0 900.0 4567.0 966.0
Segment 1 8994.0 1909.0 2366.0 2081.0 290.0 681.0
In [287]:
#repeated for ease of comparison
display(data.describe())
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
count 440.000000 440.000000 440.000000 440.000000 440.000000 440.000000
mean 12000.297727 5796.265909 7951.277273 3071.931818 2881.493182 1524.870455
std 12647.328865 7380.377175 9503.162829 4854.673333 4767.854448 2820.105937
min 3.000000 55.000000 3.000000 25.000000 3.000000 3.000000
25% 3127.750000 1533.000000 2153.000000 742.250000 256.750000 408.250000
50% 8504.000000 3627.000000 4755.500000 1526.000000 816.500000 965.500000
75% 16933.750000 7190.250000 10655.750000 3554.250000 3922.000000 1820.250000
max 112151.000000 73498.000000 92780.000000 60869.000000 40827.000000 47943.000000

Question 8

Consider the total purchase cost of each product category for the representative data points above, and reference the statistical description of the dataset at the beginning of this project. What set of establishments could each of the customer segments represent?
Hint: A customer who is assigned to 'Cluster X' should best identify with the establishments represented by the feature set of 'Segment X'.

Answer:

  1. Segment 0 would fall somewhere between the 25th and 50th percentile for Fresh, 75th and 99th percentile for Milk, 75th and 99th percentile for Grocery, 25th and 50th percentile for Frozen, 75th and 99th percentile for Detergents_Paper, and likely somewhere between 50th and 51st percentile for Delicatessen. This customer segment purchases specifically dairy products, grocery items, and household items like detergent or paper, which means it could represent stores like supermarkets, and increasingly more in the US like some drug stores or a big retailer.

  2. Segment 1 would fall somewhere between the 50th to 75th percentile for Fresh, 25th to 50th percentile for Milk, 25th and 50th percentile for Grocery, 50th and 75th percentile for Frozen, just above the 25th percentile for Detergents_Paper, and somewhere between the 25th and 50th percentile for Delicatessen. This customer segment purchases an above average amount of fresh produce and frozen goods and a below average amount of other types of goods, which means it could represent chain restaurants or cafes as they are less likely to be making big purchases of goods to sell on, but rather turn the goods into meals to serve on a smaller scale.

Question 9

For each sample point, which customer segment from Question 8 best represents it? Are the predictions for each sample point consistent with this?

Run the code block below to find which cluster each sample point is predicted to be.

In [288]:
# Redisplayed samples for ease of comparison 
display(samples)
Fresh Milk Grocery Frozen Detergents_Paper Delicatessen
0 3 2920 6252 440 223 709
1 45640 6958 6536 7368 1532 230
2 3067 13240 23127 3941 9959 731
In [289]:
# Display the predictions
for i, pred in enumerate(sample_preds):
    print "Sample point", i, "predicted to be in Cluster", pred
Sample point 0 predicted to be in Cluster 0
Sample point 1 predicted to be in Cluster 1
Sample point 2 predicted to be in Cluster 0

Answer:

Sample point 0 shows a higher proportion of Milk and Grocery than it does the other categories when compared to their relative percentiles, so it would make sense for it to be classified into Cluster 0.

Sample point 1 shows a much higher proportion of Fresh and still a high proportion of Frozen relative to the other categories, so it would make sense for it to be classified into Cluster 1.

Sample point 2 again shows a very high proportion of Milk and Grocery and additionally a high proportion of Detergents_Paper than it does the other categories, so it again would make sense for it to be classified into Cluster 0.

Conclusion

In this final section, you will investigate ways that you can make use of the clustered data. First, you will consider how the different groups of customers, the customer segments, may be affected differently by a specific delivery scheme. Next, you will consider how giving a label to each customer (which segment that customer belongs to) can provide for additional features about the customer data. Finally, you will compare the customer segments to a hidden variable present in the data, to see whether the clustering identified certain relationships.

Question 10

Companies will often run A/B tests when making small changes to their products or services to determine whether making that change will affect its customers positively or negatively. The wholesale distributor is considering changing its delivery service from currently 5 days a week to 3 days a week. However, the distributor will only make this change in delivery service for customers that react positively. How can the wholesale distributor use the customer segments to determine which customers, if any, would react positively to the change in delivery service?
Hint: Can we assume the change affects all customers equally? How can we determine which group of customers it affects the most?

Answer:

An A/B test could be conducted by trialing the 3 day a week delivery service for 20% of its customers, and leaving the 5 day a week delivery service as is for 80% of its customers as a control. It would be important to ensure that there's a representative proportion of each of the two customer segments for Group A receiving 3 day a week delivery and Group B receiving 5 day a week delivery, so that the company is able to see how each group reacts to the changes. Success could be measured qualitatively by direct feedback from the customers themselves (as there would only be 88 individual customers to track feedback from, which is 20% of the total 440), and quantitatively by comparing how the average orders and subsequent revenue for the firm increases or decreases for each group dependent on the changed delivery service.

We would hypothesise that for the customer segment that predominately purchases Milk, Grocery, and Detergents_Paper, changing the delivery service to 3 days a week from 5 days a week will likely have less of a negative effect than it would on the customer segment that predominately purchases Fresh and Frozen goods. Both purchase goods that can perish quickly; the first segment purchasing milk and baked goods (like loaves of bread), and the second purchasing fresh ingredients like fruits and vegetables. The customers would be less able to just purchase more of these goods and store them in advance than they would with non-perishable goods that make up Detergents_Paper and Frozen e.g. paper towels, washing up liquid, and frozen pizzas. However, since fresh ingredients are more likely to go off, and the second segment could be a restaurant / cafe that needs fresh ingredients each day, I think that the delivery changes would affect the second segment the most.

Question 11

Additional structure is derived from originally unlabeled data when using clustering techniques. Since each customer has a customer segment it best identifies with (depending on the clustering algorithm applied), we can consider 'customer segment' as an engineered feature for the data. Assume the wholesale distributor recently acquired ten new customers and each provided estimates for anticipated annual spending of each product category. Knowing these estimates, the wholesale distributor wants to classify each new customer to a customer segment to determine the most appropriate delivery service.
How can the wholesale distributor label the new customers using only their estimated product spending and the customer segment data?
Hint: A supervised learner could be used to train on the original customers. What would be the target variable?

Answer:

The wholesale distributer could label the new customers using their estimated product spending by looking at the relative proportions of each good they are likely to purchase. The target variable for this binary clasification problem would be the customer segment, and a supervised learner could be deployed to classify the ten new customers based on the training data of the original customers. If the customer is more likely to purchase a higher proportion of Milk, Grocery, and Detergents_Paper, then they should likely be assigned to the first segment and could be better served by the less frequent, 3-day delivery service. Additionally, if a customer is more likely to purchase a higher proportion of Fresh and Frozen goods, then they should likely be assigned to the second segment and could be better served by a more frequent, 5-day delivery service.

Visualizing Underlying Distributions

At the beginning of this project, it was discussed that the 'Channel' and 'Region' features would be excluded from the dataset so that the customer product categories were emphasized in the analysis. By reintroducing the 'Channel' feature to the dataset, an interesting structure emerges when considering the same PCA dimensionality reduction applied earlier to the original dataset.

Run the code block below to see how each data point is labeled either 'HoReCa' (Hotel/Restaurant/Cafe) or 'Retail' the reduced space. In addition, you will find the sample points are circled in the plot, which will identify their labeling.

In [290]:
# Display the clustering results based on 'Channel' data
vs.channel_results(reduced_data, outliers, pca_samples)

Question 12

How well does the clustering algorithm and number of clusters you've chosen compare to this underlying distribution of Hotel/Restaurant/Cafe customers to Retailer customers? Are there customer segments that would be classified as purely 'Retailers' or 'Hotels/Restaurants/Cafes' by this distribution? Would you consider these classifications as consistent with your previous definition of the customer segments?

Answer:

All things considered, the clustering algorithm which identified 2 clusters does a good job of classifying the points compared to the underlying distribution of Hotel/Restaurant/Cafe customers to Retailer customers. It is the case that there are a decent chunk of Hotel/Restaurant/Cafe customers that appear in what we identified as cluster 0 above when we classified them as cluster 1 (roughly 25-30), and vice versa, where there are some, although fewer (roughly 7), Retailer customers that appear in what we identifed as cluster 1 when we classified them as cluster 0. There are no segments that would be classified purely as 'Retailers' or 'Hotels/Restaurant/Cafes' by this distribution, as mentioned above there is some overlap. However, I believe we can still consider these classifications as consistent with our previous definition of customer segments; there does appear to be a general trend in purchasing behaviour by these two segments / clusters, it just seems like the Hotel/Restaurant/Cafe segment includes perhaps too many different kind of customers which leads to the characteristic purchasing behaviour of the group being slightly more diverse.

Note: Once you have completed all of the code implementations and successfully answered each question above, you may finalize your work by exporting the iPython Notebook as an HTML document. You can do this by using the menu above and navigating to
File -> Download as -> HTML (.html). Include the finished document along with this notebook as your submission.